The correct order of the oxidation states of nitrogen in NO, N2O, NO2, and N2O3, is: A
NO2
< N2O3
< NO
< N2O
B
NO2
< NO
< N2O3
< N2O
C
N2O
< N2O3
< NO
< NO2
D
N2O
< NO
< N2O3
< NO2
To determine the correct order of the oxidation states of nitrogen in the given compounds, let's analyze each compound individually:
NO (Nitric oxide): Nitrogen typically exhibits an oxidation state of +2 in NO.
N2O (Nitrous oxide): Nitrogen has an oxidation state of +1 in N2O.
NO2 (Nitrogen dioxide): Nitrogen is in the +4 oxidation state in NO2.
N2O3 (Dinitrogen trioxide): In N2O3, nitrogen is in the +3 oxidation state.
Based on this analysis, the correct order from lowest to highest oxidation state of nitrogen is: N2O < NO < N2O3 < NO2.
So, the correct answer is option D:
N2O < NO < N2O3 < NO2
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