The correct order of decreasing second ionization enthalpy of is:( Ti = 22, V = 23, Cr = 24, Mn = 25)(A) Mn > Cr > Ti > V(B) Ti > V > Cr > Mn(C) Cr > Mn > V > Ti(D) V > Mn > Cr > Ti
The correct order of decreasing second ionization enthalpy of is:( Ti = 22, V = 23, Cr = 24, Mn = 25)(A) Mn > Cr > Ti > V(B) Ti > V > Cr > Mn(C) Cr > Mn > V > Ti(D) V > Mn > Cr > Ti










