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11 grade chemistry others

The conformations of n-butane, commonly known as eclipsed, gauche and anti conformations can be interconverted by :

a.) Rotation around C - H bond of a methyl group

b.) Rotation around C - H bond of a methylene group

c.) Rotation around C1 - C2 linkage

d.) Rotation around C2 - C3 linkage

Profile image of Aniket Singh
1 Year agoGrade
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1 Answer

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Askiitians Tutor Team

ApprovedApproved Tutor Answer1 Year ago

To understand how the different conformations of n-butane can be interconverted, we need to look at the structure of n-butane and the nature of its bonds. The conformations you mentioned—eclipsed, gauche, and anti—are all related to the spatial arrangement of the atoms in the molecule, which can change through rotation around specific bonds.

Understanding n-Butane's Structure

n-Butane (C4H10) consists of a straight-chain of four carbon atoms. The key to its conformations lies in the rotation around the carbon-carbon (C-C) bonds. Each carbon atom is bonded to hydrogen atoms, and the arrangement of these atoms can lead to different spatial orientations.

Types of Conformations

  • Eclipsed Conformation: In this arrangement, the hydrogen atoms on adjacent carbons are aligned with each other, leading to increased steric strain.
  • Gauche Conformation: This occurs when the two methyl groups (CH3) are staggered but still close enough to interact, resulting in a lower energy state than the eclipsed form.
  • Anti Conformation: Here, the two methyl groups are positioned opposite each other, minimizing steric hindrance and representing the most stable conformation.

Interconversion Mechanism

The interconversion between these conformations primarily involves rotation around the C-C bonds. In n-butane, there are two significant C-C bonds: C1-C2 and C2-C3. The rotation around these bonds allows the molecule to adopt different conformations.

Which Bond Allows for Interconversion?

Among the options provided, the correct answer is:

  • c.) Rotation around C1 - C2 linkage

Rotating around the C1-C2 bond allows the molecule to transition between the eclipsed, gauche, and anti conformations. This is because the rotation changes the relative positions of the hydrogen atoms and the methyl groups on the adjacent carbon atoms.

Why Other Options Are Incorrect

Let’s briefly discuss why the other options do not facilitate the interconversion of these conformations:

  • a.) Rotation around C - H bond of a methyl group: This rotation does not significantly alter the overall conformation of the molecule since it only affects the orientation of hydrogen atoms on the methyl group itself.
  • b.) Rotation around C - H bond of a methylene group: Similar to the previous point, this rotation only affects the hydrogen atoms attached to the methylene group and does not lead to a change in the overall conformation.
  • d.) Rotation around C2 - C3 linkage: While this bond can also allow for some conformational changes, it does not directly lead to the interconversion of the primary conformations (eclipsed, gauche, anti) as effectively as the C1-C2 bond does.

Conclusion

In summary, the interconversion of n-butane's conformations is primarily achieved through rotation around the C1-C2 bond. This rotation allows the molecule to transition between the eclipsed, gauche, and anti forms, each with distinct energy levels and steric interactions. Understanding these concepts is crucial for grasping the behavior of alkanes and their conformational dynamics.