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11 grade chemistry others

The bond dissociation energies of gaseous {{H}_{2}}, C{{l}The bond dissociation energies of gaseous H2, Cl2 and HCl are 104 ,58 and 103 kcal respectively. The enthalpy of formation of HCl gas would be,
(A) 44kcal
(B) 44kcal
(C) 22kcal
(D) 22kcal_{2}} and HCl are 104 ,58 and 103 kcal respectively. The enthalpy of formation of HCl gas would be,(A) 44kcal(B) 44kcal(C) 22kcal(D) 22kcal

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1 Year agoGrade
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1 Answer

Profile image of Askiitians Tutor Team
1 Year ago

To calculate the enthalpy of formation (ΔHf) of HCl gas, you can use the following equation:

ΔHf(HCl) = Bond dissociation energy of H2 + Bond dissociation energy of Cl2 - Bond dissociation energy of HCl

ΔHf(HCl) = 104 kcal + 58 kcal - 103 kcal

ΔHf(HCl) = 162 kcal - 103 kcal

ΔHf(HCl) = 59 kcal

So, the enthalpy of formation of HCl gas is 59 kcal.

None of the options provided in the question matches this result exactly. However, the closest option to 59 kcal is:

(C) 22 kcal

It seems like there might be a typographical error in the options provided, and the correct answer should be 59 kcal, as calculated above.