Sodium hydroxide is added drop wise until in excess to a solution of zinc sulphate. Which of the following observations can be made?A) White precipitate is formed which is soluble in excess of sodium hydroxide.B) White precipitate is formed which is insoluble in excess of sodium hydroxide.C) Black precipitate is formed which is soluble in excess of sodium hydroxide.D) Black precipitate is formed which is insoluble in excess of sodium hydroxide.

To solve this question, we need to understand the chemistry of zinc sulfate (ZnSO₄) and sodium hydroxide (NaOH) and their interaction.

### Step-by-Step Explanation:

1. **Reaction Between Zinc Sulfate and Sodium Hydroxide**:
- When sodium hydroxide is added to zinc sulfate, a double displacement reaction occurs, leading to the formation of zinc hydroxide (Zn(OH)₂) and sodium sulfate (Na₂SO₄). The balanced chemical equation for this reaction is:
\[
\text{ZnSO}_4 + 2\text{NaOH} \rightarrow \text{Zn(OH)}_2 \downarrow + \text{Na}_2\text{SO}_4
\]
- Here, zinc hydroxide (Zn(OH)₂) precipitates out of the solution as a white solid.

2. **Behavior of Zinc Hydroxide**:
- Zinc hydroxide is amphoteric, meaning it can react with both acids and bases. In the presence of excess sodium hydroxide, zinc hydroxide can dissolve, forming a soluble complex ion:
\[
\text{Zn(OH)}_2 + 2\text{NaOH} \rightarrow \text{Na}_2\text{[Zn(OH)}_4\text{]}
\]
- This means that if an excess of sodium hydroxide is added, the white precipitate of zinc hydroxide will dissolve.

3. **Conclusion**:
- Based on the above points, the observation you would make when sodium hydroxide is added dropwise and then in excess to a solution of zinc sulfate is:
- A **white precipitate** (zinc hydroxide) is formed, which is **soluble** in excess of sodium hydroxide.

### Correct Answer:
**A) White precipitate is formed which is soluble in excess of sodium hydroxide.**