Negative deviation from Raoult’s law is observed in which one of the following binary liquid mixtures?A.Ethanol and acetoneB.Benzene and tolueneC.Acetone and chloroformD.Chloroethane and bromoethane

Negative deviation from Raoult's law is observed when the vapor pressure of a binary liquid mixture is lower than what would be expected based on the ideal behavior predicted by Raoult's law. This typically occurs when the interactions between the molecules of the two components in the mixture are stronger than the interactions within each pure component. In other words, when there is a more significant attraction between unlike molecules compared to like molecules.

Among the given options:

A. Ethanol and acetone: Ethanol and acetone exhibit positive deviation from Raoult's law, meaning their vapor pressures in the mixture are higher than predicted.

B. Benzene and toluene: Benzene and toluene are known to follow Raoult's law fairly closely, especially when they are considered ideal solutions. So, they typically do not exhibit strong deviations from Raoult's law.

C. Acetone and chloroform: Acetone and chloroform can exhibit negative deviation from Raoult's law due to their dissimilarity in molecular interactions.

D. Chloroethane and bromoethane: Chloroethane and bromoethane are also likely to exhibit negative deviation from Raoult's law because of their dissimilar molecular interactions.

So, the correct answer is either C (Acetone and chloroform) or D (Chloroethane and bromoethane), as both of these pairs can display negative deviatio