A Bohr diagram shows the arrangement of electrons in the shells of atoms. When making a Bohr diagram for NaCl (sodium chloride), you're dealing with the ionic bonding between sodium (Na) and chlorine (Cl). Here's a step-by-step explanation of how to create it:
1. Sodium (Na) Atom:
Atomic number: 11
Electron configuration: Sodium has 11 electrons.
First shell (K-shell) holds 2 electrons.
Second shell (L-shell) holds 8 electrons.
Third shell (M-shell) has 1 electron.
Since sodium wants to achieve a stable electron configuration, it loses 1 electron to become a sodium ion (Na⁺), which gives it the same electron configuration as neon (Ne), a stable noble gas.
Na⁺ ion configuration:
First shell: 2 electrons
Second shell: 8 electrons (the third shell is empty because sodium has lost its 1 outer electron).
2. Chlorine (Cl) Atom:
Atomic number: 17
Electron configuration: Chlorine has 17 electrons.
First shell (K-shell) holds 2 electrons.
Second shell (L-shell) holds 8 electrons.
Third shell (M-shell) holds 7 electrons.
Chlorine gains 1 electron to complete its third shell and achieve a stable electron configuration, becoming a chloride ion (Cl⁻).
Cl⁻ ion configuration:
First shell: 2 electrons
Second shell: 8 electrons
Third shell: 8 electrons (gains 1 electron to complete the shell).
3. Bohr Diagram for NaCl:
Na⁺ ion:
2 electrons in the first shell
8 electrons in the second shell
Positive charge due to the loss of 1 electron.
Cl⁻ ion:
2 electrons in the first shell
8 electrons in the second shell
8 electrons in the third shell (after gaining 1 electron).
Negative charge due to the gain of 1 electron.
In the Bohr diagram for NaCl, you'd show:
The Na⁺ ion with two filled shells (no electron in the third shell).
The Cl⁻ ion with three filled shells.
These ions are held together by the electrostatic attraction between the positively charged sodium ion and the negatively charged chloride ion (ionic bond).
This combination reflects the transfer of one electron from sodium to chlorine, creating stable ions in the process.