How much copper can be obtained from 100 g of Copper Sulphate (CuSO4)
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To determine the amount of copper that can be obtained from 100 g of copper sulfate (CuSO4), we need to consider the molar mass and stoichiometry of the compound.

The molar mass of copper sulfate (CuSO4) can be calculated by adding the atomic masses of its constituent elements:
Cu: 63.55 g/mol
S: 32.07 g/mol
O: 16.00 g/mol (x4 for four oxygen atoms)

Molar mass of CuSO4 = 63.55 + 32.07 + (16.00 x 4) = 159.61 g/mol

Now, we need to determine the molar ratio between copper (Cu) and copper sulfate (CuSO4). From the formula CuSO4, we can see that there is one copper atom (Cu) for every one copper sulfate molecule (CuSO4).

Therefore, the molar ratio between Cu and CuSO4 is 1:1.

To find the amount of copper (Cu) in 100 g of copper sulfate (CuSO4), we can use the following calculation:

Moles of CuSO4 = Mass / Molar mass
Moles of CuSO4 = 100 g / 159.61 g/mol ≈ 0.626 moles

Since the molar ratio between Cu and CuSO4 is 1:1, the moles of copper (Cu) are also approximately 0.626 moles.

To find the mass of copper (Cu), we can use the molar mass of copper (63.55 g/mol):

Mass of Cu = Moles of Cu × Molar mass of Cu
Mass of Cu = 0.626 moles × 63.55 g/mol ≈ 39.84 g

Therefore, approximately 39.84 grams of copper (Cu) can be obtained from 100 grams of copper sulfate (CuSO4).