Find the equivalent weight of potassium hydroxide.
(K=39, O=16, H=1)

A. 66μ

B. 78μ

C. 56μ

D. 43μ

To find the equivalent weight of potassium hydroxide (KOH), we need to consider the atomic masses of potassium (K), oxygen (O), and hydrogen (H) as given: K = 39, O = 16, H = 1.

The formula weight of potassium hydroxide (KOH) can be calculated by adding the atomic masses of its constituent elements:
KOH = K + O + H = 39 + 16 + 1 = 56.

The equivalent weight is the formula weight divided by the number of equivalents of the substance involved in the reaction. In the case of KOH, the number of equivalents is 1 because it donates 1 mole of hydroxide ions (OH-) per mole.

Therefore, the equivalent weight of KOH is 56 g.

Converting grams to micrograms (μg), we get:

56 g = 56,000 μg.

However, none of the provided answer choices match 56,000 μg. Therefore, none of the given options (A, B, C, or D) is correct for the equivalent weight of potassium hydroxide (KOH).