Calculate the mass of sodium acetate (C₃H₃OONa) required to make 500 mL of 0.375 M solution:

• a.) 10.45 g
• b.) 12.36 g
• c.) 15.88 g
• d.) 15.38 g

To find the mass of sodium acetate (C₃H₃OONa) needed for a 500 mL solution at 0.375 M, we can use the formula:

Formula for Molarity

Molarity (M) is defined as:

M = moles of solute / liters of solution

Step 1: Calculate Moles of Sodium Acetate

First, we need to calculate the number of moles required:

Volume of solution = 500 mL = 0.500 L

Using the molarity:

0.375 M = moles / 0.500 L

Rearranging gives:

moles = 0.375 M × 0.500 L = 0.1875 moles

Step 2: Calculate Mass of Sodium Acetate

Next, we need the molar mass of sodium acetate (C₃H₃OONa):

• C: 3 × 12.01 g/mol = 36.03 g/mol
• H: 3 × 1.01 g/mol = 3.03 g/mol
• O: 2 × 16.00 g/mol = 32.00 g/mol
• Na: 1 × 22.99 g/mol = 22.99 g/mol

Total molar mass = 36.03 + 3.03 + 32.00 + 22.99 = 94.05 g/mol

Step 3: Calculate Required Mass

Now, we can find the mass:

mass = moles × molar mass

mass = 0.1875 moles × 94.05 g/mol = 17.64 g

Final Answer

Since 17.64 g is not one of the options provided, let's double-check the calculations. The closest option to our calculated mass is:

• a.) 10.45 g
• b.) 12.36 g
• c.) 15.88 g
• d.) 15.38 g

None of these match our calculation, indicating a possible error in the options or the calculation process. However, based on our calculations, the required mass is approximately 17.64 g.