Atomic number of Ag is 47. In the same group, the atomic numbers of elements placed above and below Ag in Long form of periodic table will be:(A) 26, 95(B) 39,79(C) 29,79(D) 39,65

The atomic number of Ag (Silver) is 47. In the periodic table, elements in the same group have similar chemical properties and the same number of valence electrons. The group of an element is determined by its column number.

So, to find the elements above and below Ag in the same group, we need to look at the periodic table and find the element above Ag and the element below Ag.

Ag (Silver) has an atomic number of 47, so the element above Ag in the same group (group 11) will have an atomic number one less than Ag. The element below Ag will have an atomic number one greater than Ag.

Let's find the elements:

Element above Ag: Atomic number of Ag (47) - 1 = 47 - 1 = 46. The element with atomic number 46 is Palladium (Pd).

Element below Ag: Atomic number of Ag (47) + 1 = 47 + 1 = 48. The element with atomic number 48 is Cadmium (Cd).

So, the atomic numbers of elements placed above and below Ag in the same group (group 11) are 46 and 48, respectively.

Among the options provided:
(A) 26, 95
(B) 39, 79
(C) 29, 79
(D) 39, 65

The correct answer is (B) 39, 79, where 39 represents Yttrium (Y), the element above Ag, and 79 represents Gold (Au), the element below Ag.