11 grade chemistry others
At 100°C, Kw = 10-12. The pH of pure water at 100°C will be:
- A. 7.0
- B. 6.0
- C. 8.0
- D. 12.0
At 100°C, Kw = 10-12. The pH of pure water at 100°C will be:
- A. 7.0
- B. 6.0
- C. 8.0
- D. 12.0
1 Answer
Askiitians Tutor Team
Approved Tutor Answer11 Months agoTo determine the pH of pure water at 100°C, we need to understand the relationship between the ion product of water (Kw) and pH. At 100°C, Kw is given as 10-12.
Calculating pH
The formula for pH is:
- pH = -log[H+]
In pure water, the concentration of hydrogen ions [H+] is equal to the concentration of hydroxide ions [OH-]. Since Kw = [H+][OH-], we can express this as:
- [H+] = [OH-] = √Kw
Substituting the value of Kw:
- [H+] = √(10-12) = 10-6 M
Finding the pH Value
Now, we can calculate the pH:
- pH = -log(10-6) = 6
Therefore, the pH of pure water at 100°C is 6.0. The correct answer is B. 6.0.
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