Accomplish the conversion of aniline to ₂₄₆ - tribromofluorobenzene.

To convert aniline to 2,4,6-tribromofluorobenzene, follow these steps:

Step 1: Nitration of Aniline

Begin by nitrating aniline to form 2-nitroaniline. This can be achieved by treating aniline with a mixture of concentrated nitric acid and sulfuric acid. The reaction introduces a nitro group (-NO₂) to the aromatic ring.

Step 2: Reduction of Nitro Group

Next, reduce the nitro group of 2-nitroaniline to an amino group (-NH₂) using a reducing agent like iron and hydrochloric acid. This will yield 2,4-diaminobenzene.

Step 3: Bromination

Now, brominate the 2,4-diaminobenzene using bromine in the presence of a catalyst such as iron(III) bromide. This step will introduce bromine atoms at the 2, 4, and 6 positions of the benzene ring, resulting in 2,4,6-tribromoaniline.

Step 4: Fluorination

Finally, convert one of the amino groups in 2,4,6-tribromoaniline to a fluorine atom. This can be done using a fluorinating agent like potassium fluoride (KF) in the presence of a suitable solvent. The end product will be 2,4,6-tribromofluorobenzene.

Summary of Reagents

• Concentrated nitric acid and sulfuric acid for nitration
• Iron and hydrochloric acid for reduction
• Bromine and iron(III) bromide for bromination
• Potassium fluoride for fluorination

This sequence of reactions effectively transforms aniline into 2,4,6-tribromofluorobenzene through careful manipulation of functional groups on the aromatic ring.