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The ratio of forces between two small spheres with constant charge in air to that in a medium of dielectric constant K?

soumya , 8 Years ago
Grade 10
anser 2 Answers
Vikas TU

Last Activity: 8 Years ago

Force due to charge in air = > q1q2/(4*pi*e)r^2 = F1
Force due to charge in di – electric medium = F2
or
F2 = q1q2/(4*pi**e*K)r^2
where K is the dielectric constant.
Dividing the forces we get,
F1/ F2 = K
 

ankit singh

Last Activity: 4 Years ago

 
Force due to charge in air = > q1q2/(4*pi*e)r^2 = F1
Force due to charge in di – electric medium = F2
or
F2 = q1q2/(4*pi**e*K)r^2
where K is the dielectric constant.
Dividing the forces we get,
F1/ F2 = K

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