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molecular weight of nitric acid = 63gSpecific Gravity = 1.54% purity = 84%number of replacable hydrogens = 1Gram Equivalent Weight =molecular weight/replaceable hydrogens63/1 = 63g
Required substance weight = eq. wt. x Normality x Volume (in L)= 63gm x 0.5N X 1 Litres = 31.5 g [here Normality =molarity, as no.of H+ ions =1]Dilution Factor = Specific Gravity x concentration of pure acid.=1.54 x 0.84 = 1.3gm
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