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State the working principle of Potentiometer. Explain with the help of circuit diagram, how the potentiometer is used to determine the internal resistance of the given primary cell. In a potentiometer arrangement, a cell of emf 1.25V gives a balance point at 35cm length of the wire. If the cell is replaced by another cell and the balance point shifts to 63cm , what is the EMF of the second cell?

Harshit Singh , 4 Years ago
Grade 12th pass
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