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# If 36 ml of water is electrolysed then find the volume of oxygen and hydrogen gas obtained at their respective electrodes?

Arun
25763 Points
3 years ago
Since H2O=2H+ 1/2 O2
so 1 mole of h2o forms 2 mol h and 1/2 mol O
hence 36ml H2O= 2mol
and 2mol h2o forms 1 mol O and 4 mole H
so 16ml O and 4 ml H
Khushboo
13 Points
3 years ago
1 mole H2O = 18 ml
Therefore , 36 ml H2O = 2 mole
Now 1 mole H2O contains 2 mole H and 1mole O
Therefore 2 mole H2O has 4 mole H and 2 mole O

Oxygen and hydogen both exist as a diatomic molecule. Therefore ,
No of moles of H2 = 2
And no of moles of O2 is = 1
Total volume = 36ml
Volume of H2 and O2 are in the ratio 2:1
Therefore volume of H2 = 24 ml and
Volume of O2 = 12ml
veer
20 Points
one year ago
1 mole H2O = 18 ml
Therefore , 36 ml H2O = 2 mole
Now 1 mole H2O contains 2 mole H and 1mole O
Therefore 2 mole H2O has 4 mole H and 2 mole O

Oxygen and hydogen both exist as a diatomic molecule. Therefore ,
No of moles of H2 = 2
And no of moles of O2 is = 1
Total volume = 36ml
Volume of H2 and O2 are in the ratio 2:1
Therefore volume of H2 = 24 ml and
Volume of O2 = 12  ml