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If 36 ml of water is electrolysed then find the volume of oxygen and hydrogen gas obtained at their respective electrodes?
Since H2O=2H+ 1/2 O2so 1 mole of h2o forms 2 mol h and 1/2 mol Ohence 36ml H2O= 2mol and 2mol h2o forms 1 mol O and 4 mole Hso 16ml O and 4 ml H
1 mole H2O = 18 mlTherefore , 36 ml H2O = 2 moleNow 1 mole H2O contains 2 mole H and 1mole OTherefore 2 mole H2O has 4 mole H and 2 mole O Oxygen and hydogen both exist as a diatomic molecule. Therefore ,No of moles of H2 = 2And no of moles of O2 is = 1Total volume = 36mlVolume of H2 and O2 are in the ratio 2:1Therefore volume of H2 = 24 ml andVolume of O2 = 12ml
1 mole H2O = 18 mlTherefore , 36 ml H2O = 2 moleNow 1 mole H2O contains 2 mole H and 1mole OTherefore 2 mole H2O has 4 mole H and 2 mole O Oxygen and hydogen both exist as a diatomic molecule. Therefore ,No of moles of H2 = 2And no of moles of O2 is = 1Total volume = 36mlVolume of H2 and O2 are in the ratio 2:1Therefore volume of H2 = 24 ml andVolume of O2 = 12 ml
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