If 36 ml of water is electrolysed then find the volume of oxygen and hydrogen gas obtained at their respective electrodes?

Question

Arun · Answer

Since H2O=2H+ 1/2 O2 so 1 mole of h2o forms 2 mol h and 1/2 mol O hence 36ml H2O= 2mol and 2mol h2o forms 1 mol O and 4 mole H so 16ml O and 4 ml H

Khushboo · Answer

1 mole H2O = 18 ml Therefore , 36 ml H2O = 2 mole Now 1 mole H2O contains 2 mole H and 1mole O Therefore 2 mole H2O has 4 mole H and 2 mole O Oxygen and hydogen both exist as a diatomic molecule. Therefore , No of moles of H2 = 2 And no of moles of O2 is = 1 Total volume = 36ml Volume of H2 and O2 are in the ratio 2:1 Therefore volume of H2 = 24 ml and Volume of O2 = 12ml

veer · Answer

1 mole H2O = 18 ml Therefore , 36 ml H2O = 2 mole Now 1 mole H2O contains 2 mole H and 1mole O Therefore 2 mole H2O has 4 mole H and 2 mole O Oxygen and hydogen both exist as a diatomic molecule. Therefore , No of moles of H2 = 2 And no of moles of O2 is = 1 Total volume = 36ml Volume of H2 and O2 are in the ratio 2:1 Therefore volume of H2 = 24 ml and Volume of O2 = 12 ml

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If 36 ml of water is electrolysed then find the volume of oxygen and hydrogen gas obtained at their respective electrodes?

If 36 ml of water is electrolysed then find the volume of oxygen and hydrogen gas obtained at their respective electrodes?

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