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If 36 ml of water is electrolysed then find the volume of oxygen and hydrogen gas obtained at their respective electrodes? If 36 ml of water is electrolysed then find the volume of oxygen and hydrogen gas obtained at their respective electrodes?
Since H2O=2H+ 1/2 O2so 1 mole of h2o forms 2 mol h and 1/2 mol Ohence 36ml H2O= 2mol and 2mol h2o forms 1 mol O and 4 mole Hso 16ml O and 4 ml H
1 mole H2O = 18 mlTherefore , 36 ml H2O = 2 moleNow 1 mole H2O contains 2 mole H and 1mole OTherefore 2 mole H2O has 4 mole H and 2 mole O Oxygen and hydogen both exist as a diatomic molecule. Therefore ,No of moles of H2 = 2And no of moles of O2 is = 1Total volume = 36mlVolume of H2 and O2 are in the ratio 2:1Therefore volume of H2 = 24 ml andVolume of O2 = 12ml
1 mole H2O = 18 mlTherefore , 36 ml H2O = 2 moleNow 1 mole H2O contains 2 mole H and 1mole OTherefore 2 mole H2O has 4 mole H and 2 mole O Oxygen and hydogen both exist as a diatomic molecule. Therefore ,No of moles of H2 = 2And no of moles of O2 is = 1Total volume = 36mlVolume of H2 and O2 are in the ratio 2:1Therefore volume of H2 = 24 ml andVolume of O2 = 12 ml
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