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How to solve question no. 4 ? See in image.

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5 years ago

```							Given Voltage = V = 2VResistance = R = 1 ohmTime = t = 120 sTo findno. of electrons flowing in circuit(since all electrons flow from negativeve to positive end only)= n = ? Required FormulasOhm’s law V=IRI= Q/tQ=neV = voltage I = currentR = resistanceQ = charge t = timen = no. of electronse = charge of 1 electron  MethodBy Ohm’s lawV = IRsubstituting for V and R2V = I × 1 ohmI = 1 AnowI= Q/tIt=Qt=120sQ = 1C/s x 120sq =120 Cq= newhere n is no. of electrons and e is charge of one electronn= q/en =120/(1.6 × 10-19)n = 75 × 1019 electrons
```
5 years ago
```							I= 2 A
```
5 years ago
```							my ans is 15x1019by ohms law …..........V=IR                                 2=ixR                                 I=2as we knw that Q=ne,I=Q/t.............Q=charge,n=no. of electrns,e=charge of electrn,t=time in which charge flows2=nx1.6x10-19/2x60n=15x1019
```
5 years ago
```							sorry i made a mistake above since nobody else gave the right answer this is the real solutionGiven Voltage = V = 2VResistance = R = 1 ohmTime = t = 120 sTo findno. of electrons flowing in circuit(since all electrons flow from negativeve to positive end only)= n = ? Required FormulasOhm’s law V=IRI= Q/tQ=neV = voltage I = currentR = resistanceQ = charge t = timen = no. of electronse = charge of 1 electron  MethodBy Ohm’s lawV = IRsubstituting for V and R2V = I × 1 ohmI = 2 AnowI= Q/tIt=Qt=120sQ = 2C/s x 120sq =240 Cq= newhere n is no. of electrons and e is charge of one electronn= q/en =240/(1.6 × 10-19)n = 150 × 1019 electrons = 1.5 X 1021electrons
```
5 years ago
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