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how many 176 ohm resistors(in parallel) are required to carry 5A on a 220V line?
Given –Current,I = 5APotential difference,V = 220VResistance of each resistors = 176ohmNo. of resistors connected in parallel = ?Solution–Let total no. of resistors connected in parallel be ‘n’ so that total effective resistance be R.We know that according to Ohm’s Law,V = IRTherefore, R = V/I = 220/5 = 44ohmNow since n such resistors are connected in parallel,so 1/R = n/176or, 1/44 = n/176n = 176/44 = 4resistorsThus 4 such resistors will be required to connected in parallel.
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