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 How can three resistors of resistances 2 Ω , 3 Ω , and 6 Ω be connected to give a total resistance of (a) 4 Ω 

Pawan Prajapati , 4 Years ago
Grade 12
anser 1 Answers
Harshit Singh

Last Activity: 4 Years ago

Dear Student


When R2 and R3 are connected in parallel with R1 in series we get
1/R = 1/R2 + 1/R3
g= 1/3 + 1/6
= 1/2
Thus, R = 2 ohm
Resistance in series = R + R1
= 2 + 2
= 4 ohm

Thanks

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