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Find the potential difference across a resistor of resistance 10 ohm , if 10 to the power 20 electrons flow through it in one second.
v=IR
charge on a single electron=1.6 x 10^-19C so charge on 10^20 electrons=[1.6 x 10^-19 x 10^20]C = 16C I(current)= net charge/time A.T.Q....I = 16C/1second = 16 A so, current flowing through the resistor=16A resistance value of the resistor = 10 ohm therefore by ohm’s law i.e. V=IR Potential difference across the 10 ohm resistor= 16A x 10 ohm =160 V
Given, No. of e- = 10^20 Charge of each e- = 1.6x10^(-19) C So, charge across the resistor = 1.6x10^(-19)x10^20 = 1.6 x 10 = 16 C Resistance = 10 ohm So, by Ohm’?s Law V = IR => V = 16 x 10 => V = 160 V(Ans)
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