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Check the accuracy of relation {v^2} - {u^2} = 2as, where v and u are the final and initial velocities, a is the acceleration, and s is the distance.

Aniket Singh , 4 Months ago
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Askiitians Tutor Team

Last Activity: 4 Months ago

The relation you provided, {v^2} - {u^2} = 2as, is a valid equation for motion in one dimension under constant acceleration, such as in classical mechanics. Here's a brief explanation of each variable:

v is the final velocity.

u is the initial velocity.

a is the constant acceleration.

s is the displacement or distance traveled.
The equation represents one of the three fundamental equations of motion, specifically the one that relates final velocity, initial velocity, acceleration, and displacement. Its accuracy depends on the context and assumptions that accompany it.

However, it's important to note that this equation applies only under certain conditions:

Constant Acceleration: The equation assumes that the acceleration

a is constant over the entire interval of motion. If the acceleration changes, this equation won't be accurate.

One-Dimensional Motion: The equation describes motion along a straight line, i.e., in one dimension. It won't accurately describe motion in multiple dimensions (e.g., two-dimensional motion) without modification.

Non-Relativistic Speeds: The equation is a classical mechanics formula and isn't valid at speeds approaching the speed of light. For such cases, you would need to use relativistic physics equations.

No External Forces: This equation doesn't account for external forces acting on the object. It applies specifically to the object's motion under the influence of a constant acceleration.

So, as long as these conditions are met, the equation {v^2} - {u^2} = 2as is accurate and can be used to relate final velocity, initial velocity, acceleration, and displacement in one-dimensional motion with constant acceleration.

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