To determine which equation is balanced, we need to count the number of atoms of each element on both sides of the equations provided. Let's analyze each option:
Option A: 6HI + 2HN₃O₃ → 3I₂ + 2NO + 4H₂O
Left side: 6 H (from HI) + 2 H (from HN₃O₃) = 8 H, 6 I, 2 N, 6 O
Right side: 8 H (from 4H₂O) + 6 I (from 3I₂) + 2 N (from 2NO) + 4 O (from 4H₂O) = 8 H, 6 I, 2 N, 6 O
This equation is balanced.
Option B: 6HI + 4HN₃O₃ → 3I₂ + 2NO + H₂O
Left side: 6 H + 4 H = 10 H, 6 I, 4 N, 12 O
Right side: 2 H (from H₂O) + 8 H (from 4H₂O) + 6 I + 2 N + 0 O = 10 H, 6 I, 2 N, 1 O
This equation is not balanced.
Option C: 3HI + 2HN₃O₃ → 2I₂ + 2NO + 4H₂O
Left side: 3 H + 4 H = 7 H, 3 I, 2 N, 6 O
Right side: 8 H (from 4H₂O) + 4 I (from 2I₂) + 2 N + 0 O = 8 H, 4 I, 2 N, 0 O
This equation is not balanced.
Final Assessment
Based on the analysis, the only balanced equation is:
Option A: 6HI + 2HN₃O₃ → 3I₂ + 2NO + 4H₂O