as we know that current(I) = Q/t.........(1) but in ohms law, V is directly proportional to I Also, V is given by, V=W/Q.....(2) If we put the value of Q i.e I*t in equation (2) here we get V=W/I*t which shows that here V is inversely proportional to the current (I). How will it be possible?

Question

as we know that current(I) = Q/t.........(1) but in ohms law, V is directly proportional to I Also, V is given by, V=W/Q.....(2) If we put the value of Q i.e I*t in equation (2) here we get V=W/I*t which shows that here V is inversely proportional to the current (I). How will it be possible?

sonika p · Answer

it’s not possible. when you are writing Q in terms of current, it’s better to write even work done in terms of I. which is heat dissipated(if no other external forces are not there) W = I 2 Rt Here, R is the proportionality constant also known as resistance. Now, V = (I 2 Rt) / (I* t) = I * R, which is again Ohm’s Law. Hope it’s clear.

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as we know that current(I) = Q/t.........(1) but in ohms law, V is directly proportional to I Also, V is given by, V=W/Q.....(2) If we put the value of Q i.e It in equation (2) here we get V=W/It which shows that here V is inversely proportional to the current (I). How will it be possible?

as we know that
current(I) = Q/t.........(1)
but in ohms law, V is directly proportional to I
Also, V is given by, V=W/Q.....(2)
If we put the value of Q i.e It in equation (2) here we get V=W/It which shows that here V is inversely proportional to the current (I).
How will it be possible?

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