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an electron has a circular path of radius 0.01m in a perpendicular magnetic induction 10-3 .find the speed of the electron.

shawn john , 7 Years ago
Grade 11
anser 1 Answers
Arun

Last Activity: 7 Years ago

Dear Student
 
Force due to magnetic field = Bqv
Centripetal Force = mv²/r

Centripetal Force is provided by magnetic field.
So,
Force due to magnetic field = Centripetal Force
Bqv = mv² / r
v = Bqr / m
= (10^-3 T × 1.6 × 10^-19 C × 0.01 m) / (9.1 × 10^-31 kg)
= 1.76 × 10^6 m/s

Speed of electron is 1.76 × 10^6 m/s
 
 
Regards
Arun (askIITians forum expert)

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