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Grade: 8
        An electron has a circular path of radius 0.01m  in a perpendicular magnetic induction 10^-3T. Find the speed of electron.
9 months ago

Answers : (1)

Arun
13939 Points
							
Dear student
 
Bqv = mv² / r

v = Bqr / m
= (10⁻³ T × 1.6 × 10⁻¹⁹ C × 0.01 m) / (9.1 × 10⁻³¹ kg)
= 1.76 × 10⁶ m/s
Speed of electron is 1.76 × 10⁶ m/s
 
 
Regards
Arun (askIITians forum expert)
9 months ago
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