a wooden cube floats in water partially immersed,when 200g weight is put on it. it is further immersed by 2cm.the lenght of the side of the cube is?

Question

Arun · Answer

Dear student

Let length of one edge = x
Vol. of cube = L*B*W
Vol. of cube = x*x*x
Vol. of cube = x^3
Vol. of cube = Area * height.
Vol. of cube = x² * 2
Vol. of cube = 2x² cm^3
200 mg = 2x²
x² = 200 mg / 2
x = | ± √100 |
x = 10 cm

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Arun (askIITians forum expert)

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a wooden cube floats in water partially immersed,when 200g weight is put on it. it is further immersed by 2cm.the lenght of the side of the cube is?

a wooden cube floats in water partially immersed,when 200g weight is put on it. it is further immersed by 2cm.the lenght of the side of the cube is?

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a wooden cube floats in water partially immersed,when 200g weight is put on it. it is further immersed by 2cm.the lenght of the side of the cube is?

a wooden cube floats in water partially immersed,when 200g weight is put on it. it is further immersed by 2cm.the lenght of the side of the cube is?

1 Answers

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