badge image

Enroll For Free Now & Improve Your Performance.

×
User Icon
User Icon
User Icon
User Icon
User Icon

Thank you for registering.

One of our academic counsellors will contact you within 1 working day.

Please check your email for login details.
MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
Menu
Grade: 10

                        

A thin glass of refractive index 1.5 has optical power -5D in air . What will be the optical power of the same lens immersed in a liquid of refractive index 1.6

3 years ago

Answers : (1)

Aditya kashyap
32 Points
							P= 1/f  = (U-1)(1/r1 - 1/r2)   is lens maker formula  .... where U is refractive index of medium..     Now p1/p2=  (Uga-1)(1/r1 - 1/r2) /(Ugl-1)(1/r1 - 1/r2) ... As r1 and r2 is same in both medium...So   p1/p2= (Uga-1)/(Ugw-1) ....    p1/p2= (Ug/Ua-1)/(Ug/Uw-1)...Here, p1 =-5,Ug=1.5,Ua=1,Uw=1.6....   -5/P2=(1.5 -1)/(1.5/1.6 -1)..  -5/P2=(0.5)/(-0.1/1.6)....    P2= 1/1.6 .....    P2 =0.625 D.
						
2 years ago
Think You Can Provide A Better Answer ?
Answer & Earn Cool Goodies


Course Features

  • 731 Video Lectures
  • Revision Notes
  • Previous Year Papers
  • Mind Map
  • Study Planner
  • NCERT Solutions
  • Discussion Forum
  • Test paper with Video Solution


Course Features

  • 731 Video Lectures
  • Revision Notes
  • Test paper with Video Solution
  • Mind Map
  • Study Planner
  • NCERT Solutions
  • Discussion Forum
  • Previous Year Exam Questions


Ask Experts

Have any Question? Ask Experts

Post Question

 
 
Answer ‘n’ Earn
Attractive Gift
Vouchers
To Win!!! Click Here for details