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A ray of light is incident on a prism in the minimum deviation position as shown and it suffers a deviation of 40 degree. what will be the deviation suffered if the colored half of prism is removed?

A ray of light is incident on a prism in the minimum deviation position as shown and it suffers a deviation of 40 degree. what will be the deviation suffered if the colored half of prism is removed?

Question Image
Grade:10

1 Answers

Kenny Toijam
56 Points
5 years ago
The answer to this question is 20°
Solution:
∂(min)=2i-A(which is the initial prism angle)
r1+r2  = A
So    40= 2i-A-------------------------(1)
           i =20+(A/2)
Now after the colored side has been removed light will emerge out parallel to the base of the prism after refraction from 1st face
Therefore r2=0 -------->    r1=A/2
Now new prism angle is A/2
therefore
∂(new) = i1 + i2  –  (A/2)
              = i + 0 – (A/2)
             =20 +(A/2) – (A/2)
             = 20° Which is the new angle of deviation
Hope it helps..
Regards,
Kenny Toijam

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