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A man weighs W on the surface of earth. What is his weight at a height equal to radius of the earth

SUDHARSANA V V , 7 Years ago
Grade 10
anser 1 Answers
Arun

Last Activity: 7 Years ago

Weight is inversely proportional to square of distance between man and centre of earth
W ∝ 1/d^2

Initial distance when weight = W is R
When it is at a height R distance is 2R

W₁/W₂ = (d₂/d₁)^2
W/W₂ = (2R/R)^2
W/W₂ = 4
W₂ = W/4
 
Regards
Arun (askIITians forum expert)

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