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A circuit consists of  3 resisters of  12,18,and 36 ohms  respectvely by join in parallel and the combination is  connected in series with a resister of  12 ohms the hole  circuit is connected to a 60 v supply calculate current in each branch,total current drown and power dispates in each resister?
one year ago

Arun
19063 Points

P1 = V^2 / R1,
P1 = V^2 / 12 = 36 W.
V^2 = 12*36 = 432,
V=20.8 Volts. = Voltage across R1,R2,R3

I1 = V1 / R1 = 20.8 / 12 = 1.73A.
I2 = 20.8 / 18 = 1.16A.
I3 = 20.8 / 36 = 0.578A.

I4=I1 + I2 + I3 = 1.73 + 1.16 + 0.578 =
3.47A.

R4=V4 / I4 = (60 - 20.8) / 3.47 = 11.3
Ohms.

Pt=E*It = E*I4 = 60 * 3.47 = 208 Watts
one year ago
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### Course Features

• 731 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions