 Click to Chat

1800-2000-838

+91-120-4616500

CART 0

• 0

MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
`        A circuit consists of  3 resisters of  12,18,and 36 ohms  respectvely by join in parallel and the combination is  connected in series with a resister of  12 ohms the hole  circuit is connected to a 60 v supply calculate current in each branch,total current drown and power dispates in each resister?`
one year ago

## Answers : (1)

```							P1 = V^2 / R1, P1 = V^2 / 12 = 36 W. V^2 = 12*36 = 432, V=20.8 Volts. = Voltage across R1,R2,R3 I1 = V1 / R1 = 20.8 / 12 = 1.73A. I2 = 20.8 / 18 = 1.16A. I3 = 20.8 / 36 = 0.578A. I4=I1 + I2 + I3 = 1.73 + 1.16 + 0.578 = 3.47A. R4=V4 / I4 = (60 - 20.8) / 3.47 = 11.3 Ohms. Pt=E*It = E*I4 = 60 * 3.47 = 208 Watts
```
one year ago
Think You Can Provide A Better Answer ?
Answer & Earn Cool Goodies

## Other Related Questions on 10 grade science

View all Questions »  ### Course Features

• 731 Video Lectures
• Revision Notes
• Previous Year Papers
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Test paper with Video Solution  ### Course Features

• 731 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions