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Grade: 12th pass
        A circuit consists of  3 resisters of  12,18,and 36 ohms  respectvely by join in parallel and the combination is  connected in series with a resister of  12 ohms the hole  circuit is connected to a 60 v supply calculate current in each branch,total current drown and power dispates in each resister?
9 months ago

Answers : (1)

Arun
15880 Points
							
P1 = V^2 / R1, 
P1 = V^2 / 12 = 36 W. 
V^2 = 12*36 = 432, 
V=20.8 Volts. = Voltage across R1,R2,R3 

I1 = V1 / R1 = 20.8 / 12 = 1.73A. 
I2 = 20.8 / 18 = 1.16A. 
I3 = 20.8 / 36 = 0.578A. 

I4=I1 + I2 + I3 = 1.73 + 1.16 + 0.578 = 
3.47A. 

R4=V4 / I4 = (60 - 20.8) / 3.47 = 11.3 
Ohms. 

Pt=E*It = E*I4 = 60 * 3.47 = 208 Watts
9 months ago
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