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```
3 resistors 4 ohm,6 ohm and 12 ohm are connected in parallel.The combination of the above resistors is connected in series to a resistance of 2 ohm and then to a battery of 6 volt. draw a circuit diagram and calculate: a)current in the main circuit. b)current flowing through each of the resistors in parallel. c)potential difference across the 2 ohm resistor. (diagram is not necessary).

```
5 years ago

```							Given-R1 = 4ohmR2 = 6ohmR3 = 12ohmRs = 2ohm (Series resistor)Potential difference,V = 6VLet the resistance of all three resistors which are connected in parallel be RpThen,1/Rp = 1/R1 +1/R2 + 1/R31/Rp = 1/4 + 1/6 + 1/121/Rp = 6/12or,Rp = 12/6 = 2ohmLet total resistance be Rt = Rp +Rs Rt = 2 + 2 = 4ohma).So current,I in the main circuit will be V=IRtherefore, I = V/R = 6/4 = 1.5A which is total current.b) Since in parallel the current will divided into three resistors connected in parallel.Let the current across all the three be I1,I2 and I3.Now,I1 = V/R1 (Since potential difference is same as they are connected in parallel)I1 = 6/4 = 1.5ASimilarly,I2 = V/R2I2 = 6/6 = 1Aand I3 = 6/12 = 0.5Ac). V across 2ohm resistor will be- V = I*R ( I will be total current)V = 1.5 * 2 = 3V
```
5 years ago
```							will someone post  the proper answer.plzz
```
5 years ago
```							Dear student i am again explaining the question you have asked.As per your question three resistors(4,6,12 ohm respectively)are connected in parallel and then connected in series with 2ohm resistor(Rs).Now,a).The first part of question is asking about the current in the main circuit.So first we have to find the total resistance which we suppose to designated as Rt.For parallel combination1/Rp = 1/R1 + 1/R2 + 1/R3 1/Rp = 1/4 + 1/6 + 1/12Rp = 12/6 = 2ohmFor total resistance,Rt = Rp + Rs (Since all three connected in series with the 2ohm resistor) Rt = 2 + 2 = 4ohm According to Ohm’s law, V = I*RI = V/R = 6/4 = 1.5A (Since the whole combination is connected to a battery of 6V)b).Second part is asking the current through each resistor connected in parallel.Since in parallel combination current will get divided into three part each through the three resistors(I1,I2 and I3).Voltage in such combination remains same.So I1 = V/R1 , I2 = V/R2 and I3 = V/R3 which we calculated as explained above.3).Third part is asking the voltage across 2ohm resistor.Let it be Vs Vs = I * Rs For that main current which is calculated as above will be used as this resistor is connected in series so the main current will passes through it also. Vs = 1.5 * 2 = 3V
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5 years ago
```							lets find parallel resistance first = 24/12 = 2ohmp = 1/4 + 1/6 + 1/12=12/24Rp1/R3  + 1/R2 + 1/R1= 1/Rp 1/R total resistance=Rp + Rs = 2 + 2 = 4ohmcurrent in circuit=i=V/R=6/4=1.5ampcurrent flow is diff in all parallel resistors and potential diff is same in all parallel resistors but not same as series resistor.Vp potential diff across parallel resistors,Vs potential diff aross series resistorV=Vp+VsVs=I(2)=(1.5)2=3VVp=V-Vs=6-3=3Vcurrent through R1 is            I1=Vp/R1=3/4 ampcurrent through  R2 is           I2=Vp/R2=3/6=1/2ampcurrent through R3 is         I3=Vp/R3=3/12=1/4amp approve if it is r8
```
5 years ago 605 Points
```							Dear student,Please find the attached solution to your problem. The resultant resistance from the parallel arrangement1/Rp = 1/4+ 1/6 + 1/12 = 6/12Hence, Rp = 2ΩNow total resistance in circuit = Rp + Rs = 2 + 2 = 4Ω a). current in circuit, I = V/R = 6/4 = 1.5 A b). Now the potential difference across the circuit will be the sum of potential drop across the two arrangements.Hence, V = Vp + VsVs = I(2) = (1.5)2 = 3VVp = V – Vs = 6 – 3 = 3Vcurrent through R1, I1 = Vp/R1 =  0.75 Acurrent through  R2, I2 = Vp/R2 = 3/6 = 0.5 Acurrent through R3, I3 = Vp/R3 = 3/12 = 0.25 A c). We have already calculated, Vs = 3 V Thanks and regards,Kushagra
```
3 months ago
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