Thank you for registering.

One of our academic counsellors will contact you within 1 working day.

Please check your email for login details.
MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping

Write a Pythagorean triplet whose one member is: A) 6 B) 14 C) 16 D) 18

Write a Pythagorean triplet whose one member is:
A) 6
B) 14
C) 16
D) 18

Grade:12th pass

1 Answers

Pawan Prajapati
askIITians Faculty 9723 Points
19 days ago
Let us first understand the term Pythagorean triplet and then we will use a formula to determine all the numbers in a Pythagorean triplet of the given options one by one. First, we will divide the given number by two, then we will use n2−1 and n2+1 to determine the other two numbers. Complete step-by-step solution: A Pythagorean Triplet is one in which the square of one of the integers in the triplet equals the sum of the squares of the other two numbers. Pythagorean triplets are the result of Pythagoras' right-angled triangle theorem, which states that the sum of the squares of the lengths of the sides other than the hypotenuse in a right-angled triangle is equal to the square of the hypotenuse's length. Now, we will look at the method that we are going to apply to derive the triplet. The three numbers that are used as a Pythagorean triplet can be represented as 2n , n2−1 and n2+1 . That means we have to assume our number as 2n and hence we will be able to determine the other two. A) 6 Let’s us assume that 2n=6 Therefore, by dividing 2, we will get the value of n as, ⇒n=62 ⇒n=3 Now, by putting the value of n on the other formulas, we get ⇒n2−1=32−1 ⇒n2−1=8 and ⇒n2+1=32+1 ⇒n2+1=10 Therefore, the Pythagorean triplet containing 6 is 6, 8 and 10. B) 14 Again, let’s assume that 2n=14 ⇒n=7 And by putting the value of n, we get ⇒n2−1=72−1 ⇒n2−1=48 And, ⇒n2+1=72+1 ⇒n2+1=50 Hence, the Pythagorean triplet containing 14 is 14, 48 and 50. C) 16 Now, let’s assume that 2n=16 ⇒n=8 By putting the value of n, we get ⇒n2−1=82−1 ⇒n2−1=63 And, ⇒n2+1=82+1 ⇒n2+1=65 Therefore, the Pythagorean triplet containing 16 is 16, 63 and 65 D) 18 Finally, let’s assume 2n=18 ⇒n=9 By putting the value of n, we get ⇒n2−1=92−1 ⇒n2−1=80 And ⇒n2+1=92+1 ⇒n2+1=82 Hence, the Pythagorean triplet containing 18 is 18, 80 and 82. Note: We can clearly say that the length of the hypotenuse is the largest. Hence, n2+1 denotes the largest side i.e. hypotenuse. Also, make sure that after getting the Pythagorean triplet, the length should fulfill the condition of the Pythagoras theorem i.e. H2=P2+B2 .

Think You Can Provide A Better Answer ?

Provide a better Answer & Earn Cool Goodies See our forum point policy

ASK QUESTION

Get your questions answered by the expert for free