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WHAT IS THE REMAINDER WHEN 4^96 IS DIVIDED BY 6?
According to euclid`s algorithm a=bq+r Let a=16 (4^2) and b=6 then 16=6*2+4 Let a=64 (4^3) and b=6 then 64=6*10+4 Let a=256 (4^4) and b=6 then 256=6*42+4 If we continue in this manner, we find that the remainder for any power of 4 when divided by 6 will be 4 only. Hence the remainder for 4^96 when divided by 6 will be 4.
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