The sum of all odd integers between 2 and 100 divisible by 3 is
(a) 17
(b) 867
(c) 876
(d) 786

Question

The sum of all odd integers between 2 and 100 divisible by 3 is (a) 17 (b) 867 (c) 876 (d) 786

Pawan Prajapati · Answer

Answer: b Explaination:Reason: The numbers are 3, 9,15, 21, …, 99 Here a = 3, d = 6 and an = 99 ∴ an = a + (n – 1 )d ⇒ 99 = 3 + (n – 1) x 6 ⇒ 99 = 3 + 6n – 6 ⇒ 6n = 102 ⇒ n = 17

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The sum of all odd integers between 2 and 100 divisible by 3 is (a) 17 (b) 867 (c) 876 (d) 786

The sum of all odd integers between 2 and 100 divisible by 3 is
(a) 17
(b) 867
(c) 876
(d) 786

1 Answers

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The sum of all odd integers between 2 and 100 divisible by 3 is (a) 17 (b) 867 (c) 876 (d) 786

The sum of all odd integers between 2 and 100 divisible by 3 is (a) 17 (b) 867 (c) 876 (d) 786

1 Answers

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The sum of all odd integers between 2 and 100 divisible by 3 is
(a) 17
(b) 867
(c) 876
(d) 786