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Grade 12th pass10 grade maths

tanA+sinA=m, tanA-sinA=n.
Then prove that, √mn=tanA.sinA

Profile image of Mahmudul Hasan
7 Years agoGrade 12th pass
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1 Answer

Profile image of Niranjan Pandey of Cambridge
7 Years ago
A/q    mn= (tanA+sinA)(tanA-sinA)
              =tan2A-sinAtanA+sinAtanA-sin2A
              =tan2A-sin2A
              =(tanA+sinA)(tanA-sinA)
              =(sinA/cosA + sinA)(sinA/cosA – sinA)
              ={(sinA+sinAcosA)/cosA}{(sinA-sinAcosA)/cosA}
              ={sinA(1+ cosA)/cosA}{sinA(1- cosA)/cosA}
              ={sin2A(1-cosA2)}/cos2A
              ={sin2A(sin2A)}/cos2A
   √mn   =sinAsinA/cosA
              =sinA*sinA/cosA
              =sinA*tanA
              =tanAsinA