sin(A+B).sin(A-B)=cos^2B-cos^2A

Question

Vijay Mukati · Answer

Dear student,sin(A+B).sin(A-B)=sin 2 A-sin 2 B and can be easily proved. Now you can use the identity sin 2 A + cos 2 A =1 to prove sin(A+B).sin(A-B)=cos 2 B-cos 2 A. Thanks

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sin(A+B).sin(A-B)=cos^2B-cos^2A

sin(A+B).sin(A-B)=cos^2B-cos^2A

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sin(A+B).sin(A-B)=cos^2B-cos^2A

sin(A+B).sin(A-B)=cos^2B-cos^2A

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