sin (45° + θ) – cos (45° – θ) is equal to
(a) 2 cos θ
(b) 0
(c) 2 sin θ
(d) 1

Question

sin (45° + θ) – cos (45° – θ) is equal to (a) 2 cos θ (b) 0 (c) 2 sin θ (d) 1

Pawan Prajapati · Answer

Answer: b Explaination: sin (45° + θ) – cos (45° – θ) = sin {90° – (45° – θ)} – cos (45° – θ) = cos (45° – θ) – cos (45° – θ) = 0

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sin (45° + θ) – cos (45° – θ) is equal to (a) 2 cos θ (b) 0 (c) 2 sin θ (d) 1

sin (45° + θ) – cos (45° – θ) is equal to
(a) 2 cos θ
(b) 0
(c) 2 sin θ
(d) 1

1 Answers

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sin (45° + θ) – cos (45° – θ) is equal to (a) 2 cos θ (b) 0 (c) 2 sin θ (d) 1

sin (45° + θ) – cos (45° – θ) is equal to (a) 2 cos θ (b) 0 (c) 2 sin θ (d) 1

1 Answers

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sin (45° + θ) – cos (45° – θ) is equal to
(a) 2 cos θ
(b) 0
(c) 2 sin θ
(d) 1