To show that triangles ABC and PQR are similar, we can use the concept of "triangle proportionality" or "triangle similarity."
Given:
Side AB of triangle ABC is proportional to side PQ of triangle PQR.
Side AC of triangle ABC is proportional to side PR of triangle PQR.
Median AD of triangle ABC is proportional to median PM of triangle PQR.
We want to prove that triangle ABC is similar to triangle PQR, which can be denoted as ΔABC ∼ ΔPQR.
In order to prove the similarity of two triangles, we need to show that their corresponding angles are congruent, and their corresponding sides are proportional.
Let's start by showing the angle congruence:
We know that AD is a median in triangle ABC, so it divides side BC into two equal parts. Therefore, BD = DC.
Similarly, PM is a median in triangle PQR, so it divides side QR into two equal parts. Therefore, QM = MR.
Now, let's consider the following ratios:
AB/PQ (given) and BD/QM (because BD = DC)
AC/PR (given) and DC/MR (because DC = BD)
AD/PM (given)
We can write these ratios as:
(AB/PQ) = (BD/QM)
(AC/PR) = (DC/MR)
(AD/PM)
Now, let's combine these ratios:
(AB/PQ) * (AC/PR) * (AD/PM) = (BD/QM) * (DC/MR)
Since BD = DC and QM = MR, we have:
(AB/PQ) * (AC/PR) * (AD/PM) = (BD/BD) * (DC/DC)
The right side simplifies to 1:
(AB/PQ) * (AC/PR) * (AD/PM) = 1
Now, we have shown that the product of these ratios is equal to 1. According to the Angle-Angle Similarity Theorem (AA similarity), if the product of corresponding sides in two triangles is equal to 1, and their corresponding angles are congruent, then the triangles are similar.
Since we have shown that the ratios of the sides are equal to 1, and we have not made any specific angle measurements or assumptions, we can conclude that triangles ABC and PQR are similar by the AA similarity theorem.
Therefore, we have successfully shown that ΔABC ∼ ΔPQR based on the given proportions of sides and medians.