Pushkar Aditya
Last Activity: 10 Years ago
Any odd positive integer is of the form 4m + 1 or 4m + 3 for some integer m.
When n = 4m + 1,
n2 – 1 = (4m + 1)2 – 1 = 16m2 +8m+1 – 1= 16m2+8m = 8m(2m+1)
n2 – 1 is divisible by 8.
When n = 4m + 3
n2 – 1 = (4m+3) – 1 = 16m2 + 24m + 9 – 1 = 16m2 + 24m + 8 = 8(2m2 + 3m + 1)
n2 – 1 is divisible by 8.
Hence, n2 – 1 is divisible by 8 if n is an odd positive integer.