Grade 910 grade maths
SecA(1+secA)(secA-tanA)=1 prve it with explaination
1 Answer
Shailendra Kumar Sharma
A-TanA)Which cannot be zero the question is wrong2A -SecA-TanA)LHS= (SecA-TanA)(Sec2A) = 0:LHS= (SecA-TanA)(SecA+Sec2A-tan2SecA(1+secA)(secA-tanA) – (secSecA(1+secA)(secA-tanA)=1
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