(sec A - cosec A)(1+ tan A + cot A) = tan A sec A- cot A cosec A

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Saurabh Koranglekar · Answer

Dear student Please ask complete question Regards

Vikas TU · Answer

Dear student 1/CosA - 1/SinA (1+sinA/CosA + CosA/SinA) = (SinA-cosA)/SinAcosA)((SinACosA + Sin^2A + Cos^2A)/(SinACosA) =(Sin^3A - Cos^3A) /SinA CosA = TanA SecA - CotACosecA

Arun · Answer

Dear student LHS (1/ cosA - 1/sinA ) (1 + sinA/cosA + cosA /sinA) = ((SinA-cosA)/sinA cosA)((sinA cosA + sin²A + cos²A)/sinA cos A) = (Sin³A - cos³A)/ sinA cosA = TanA secA - cotA cosecA RHS Hence proved.

Yashraj · Answer

please ask what to do in this question with my best regards type the full question or attach the image

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(sec A - cosec A)(1+ tan A + cot A) = tan A sec A- cot A cosec A

(sec A - cosec A)(1+ tan A + cot A) = tan A sec A- cot A cosec A

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