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sec(1+tan)+cos1(+cot)=sec+cosecHow to find it.sec(1+tan)+cos1(+cot)=sec+cosecsec(1+tan)+cos1(+cot)=sec+cosec

sec(1+tan)+cos1(+cot)=sec+cosecHow to find it.sec(1+tan)+cos1(+cot)=sec+cosecsec(1+tan)+cos1(+cot)=sec+cosec

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Grade:10

1 Answers

Ankit
104 Points
3 years ago
My friend the question is slightly wrong.In lhs `sin` would come instead of `sec`.Now Sin(1+sin/cos) + cos(1+cos/sin)=Sin(cos+sin) + cos (sin+cos) ________. ________ Cos. Sin= (Sin+cos)(sin/cos + cos/sin)=(Sin + cos)(sin^2+cos^2) _____________ Sin×Cos=(Sin+cos)(1/sin×cos)=(Sin+cos)/sin×cos=Sec + cosec hence proved

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