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Question 25.......................................................

Question 25.......................................................

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1 Answers

Varish
13 Points
one year ago
There will be two coincidence zeroes.
Here we can see that f(x) = x2 + 2x+1 and g(x) = x2-2x+1.These polynomials satisfy all the given conditions.
Hence the product of f(x).g(x) will be (x+1)2.(x-1)2 on equating it to zero we will get four zeroes namely 1, 1, i and -i.
Two real repeated zeroes are possible in this case.

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