prove that. (x+yw+zw^2)^5+(xw+yw^2+z)^5+(xw^2+y+zw)^5=0

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Arun · Answer

Dear student I didn't get any method how to solve this is there any pre relation between them. Please attach the image of the question. I will be happy to help you

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prove that. (x+yw+zw^2)^5+(xw+yw^2+z)^5+(xw^2+y+zw)^5=0

prove that. (x+yw+zw^2)^5+(xw+yw^2+z)^5+(xw^2+y+zw)^5=0

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