Grade 1110 grade maths
Plz solve question 3 plzzzzzzzaaaa......................
Plz solve question 3 plzzzzzzzaaaa......................
1 Answer
Arun
Dear student
x= (1/6)^200
On taking log
log x = log (1/6)^200
log x = 200 * log (1/6)
log x = 200 * (-0.788...)
log x = -155.6
log x = log (1/6)^200
log x = 200 * log (1/6)
log x = 200 * (-0.788...)
log x = -155.6
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