Grade 1010 grade maths
Please solve ......................................
Please solve ......................................
1 Answer
Arun
Approved Tutor Answer7 Years agoAll the natural numbers starting from 1 are enlisted:
So number of 1 digit numbers = 9
number of 2 digit numbers = 90(to calculate number of digits we need to multiply by 2)
number of 3 digit numbers starting from 100 till 699 = 600(to calculate number of digits we need to multiply by 3)
So, starting from 1 to 699, total number of digits will be
9 + 2*90 + 3*600 = 1989.
If we also add 700-704 we get total 1989 + 15 = 2004 digits enlisted.
Now the 2006 digit in the sequence is clearly evident that would be the second digit of 705 which is 0.
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