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Please give the solution for Q.No 17 and 18 with explanation
note that 3x^2 + 5y^2 + 4z^2 – 4xy – 4xz – 4x – 2y + 25= (x – 2)^2 + (y – 1)^2 + (x – 2y)^2 + (x – 2z)^2 + 20.for this expression to b min, all square terms can be made zero.so x= 2, y= 1, x= 2z or z= 1.hence minimum value is 20.kindly approve :)
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