Let N be the greatest number that will divide 1305, 4665 and 6905 leaving the same remainder in each case. The sum of digits of N is
(a) 4(b) 5(c) 6(d) 8

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Let N be the greatest number that will divide 1305, 4665 and 6905 leaving the same remainder in each case. The sum of digits of N is (a) 4(b) 5(c) 6(d) 8

Pawan Prajapati · Answer

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Let N be the greatest number that will divide 1305, 4665 and 6905 leaving the same remainder in each case. The sum of digits of N is (a) 4(b) 5(c) 6(d) 8

Let N be the greatest number that will divide 1305, 4665 and 6905 leaving the same remainder in each case. The sum of digits of N is
(a) 4(b) 5(c) 6(d) 8

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Let N be the greatest number that will divide 1305, 4665 and 6905 leaving the same remainder in each case. The sum of digits of N is (a) 4(b) 5(c) 6(d) 8

Let N be the greatest number that will divide 1305, 4665 and 6905 leaving the same remainder in each case. The sum of digits of N is (a) 4(b) 5(c) 6(d) 8

1 Answers

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Let N be the greatest number that will divide 1305, 4665 and 6905 leaving the same remainder in each case. The sum of digits of N is
(a) 4(b) 5(c) 6(d) 8