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10 grade maths

Karl Pearson’s coefficient of skewness of a distribution is 0.32, its S.D is 6.5 and mean is 29.6. The mode and median of the distribution are

  • ( A ) 27.52, 28.91
  • ( B ) 26.92, 27.23
  • ( C ) 25.67, 26.34
  • ( D ) None of these

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0 Years agoGrade
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1 Answer

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ApprovedApproved Tutor Answer0 Years ago

To find the mode and median of the distribution given Karl Pearson’s coefficient of skewness, we can use the formula for skewness, which is defined as:

Understanding Skewness

Karl Pearson’s coefficient of skewness (Sk) is calculated using the formula:

Sk = 3(Mean - Median) / Standard Deviation

In this case, we know:

  • Sk = 0.32
  • Mean = 29.6
  • Standard Deviation (SD) = 6.5

Finding the Median

We can rearrange the skewness formula to solve for the median:

Median = Mean - (Sk * SD) / 3

Substituting the known values into the equation:

Median = 29.6 - (0.32 * 6.5) / 3

Calculating the product:

0.32 * 6.5 = 2.08

Now, dividing by 3:

2.08 / 3 = 0.6933

Finally, substituting back to find the median:

Median = 29.6 - 0.6933 = 28.9067

Rounding this, we get approximately 28.91.

Finding the Mode

Next, we can use the relationship between mean, median, and mode in a skewed distribution. The formula is:

Mode = 3 * Median - 2 * Mean

Substituting the values we have:

Mode = 3 * 28.91 - 2 * 29.6

Calculating this step-by-step:

  • 3 * 28.91 = 86.73
  • 2 * 29.6 = 59.2

Now, subtracting the two results:

Mode = 86.73 - 59.2 = 27.53

Rounding this gives us approximately 27.52.

Final Results

Based on our calculations, we find:

  • Median ≈ 28.91
  • Mode ≈ 27.52

Thus, the correct answer is option (A): 27.52 for the mode and 28.91 for the median.